If alpha and beta are the zeros of polynomial x^2-4x+3 form a quadratic polynomial whose zeroes are 3alpha and 3beta
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x2-5x+k
Here, a=1, b=-5 and c=k
Now, alpha+beta= -b/a= -(-5)/1= 5
alpha*beta= c/a= k/1= k
Now, apha-beta=1
Squaring both sides, we get,
(alpha-beta)2=12
=> (alpha+beta)2-4*aplha*beta=1
=> (5)2-4k=1
=> -4k= 1-25
=> -4k= -24
=> k=6
So the value of k is 6.
Hope it helps!!
Here, a=1, b=-5 and c=k
Now, alpha+beta= -b/a= -(-5)/1= 5
alpha*beta= c/a= k/1= k
Now, apha-beta=1
Squaring both sides, we get,
(alpha-beta)2=12
=> (alpha+beta)2-4*aplha*beta=1
=> (5)2-4k=1
=> -4k= 1-25
=> -4k= -24
=> k=6
So the value of k is 6.
Hope it helps!!
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