Question

if alpha and beta are the zeros of polynomial X square + 6 X + 9 then form a polynomial whose zeros are minus alpha and minus beta​

Answer 1

Answer:

x² - 6x + 9

Step-by-step explanation:

Given polynomial: p(x) = x² + 6x + 9

Its zeroes are α and β.

α + β = -b/a = -6/1 = -6

So, -α -β = 6 or -1(α+β) = 6

Also, α.β = c/a = 9/1 = 9

So, -α × -β = α×β = 9

We know that Q.P = k(x² - (Sum of zeroes)x + (Product of zeroes)), where k is constant term.

So, the new Q.P. will be k(x² - (6)x + 9) = k(x² - 6x + 9)

Considering k to be 1, the Q.P. is

x² - 6x + 9

Answer 2

Answer:

Step-by-step explanation: