if alpha and beta are the zeros of polynomial X square + 7 x + 12 then from a quadratic polynomial whose zeros are 2 alpha and 2 beta
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Answer:
The polynomial whose zeros are 2α and 2β is x² + 14x + 48
Explanation:
Given polynomial,
⇒ x² + 7x + 12
Whose zeros are α and β
We need to find the polynomial whose zeros are 2α and 2β
Let's calculate α and β :-
On factorising the polynomial,
⇒ x² + 3x + 4x + 12
⇒ x(x + 3) + 4(x + 3)
⇒ (x + 3) + (x + 4)
Then, zeros of the polynomial are -3 and -4
∴ α = -3 and β = -4
Now,
New zeros are :-
→ 2α
→ 2(-3)
→ -6
And also,
→ 2β
→ 2(-4)
→ -8
The required polynomial is given by,
→ x² - (sum of zeros)x + product of zeros
→ x² - [(-6) + (-8)]x + (-6)*(-8)
→ x² - [ - 6 - 8 ]x + 48
→ x² - [ -14]x + 48
→ x + 14x + 48
Required answer: x² + 14x + 48
____________________
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