Question

if alpha and beta are the zeros of polynomial X²+ 6x + 8 find the value of alpha+beta- Alpha beta ​

Answer 1

p(x) = x² + 6x + 8

a = 1

b = 6

c = 8

Given α and β are zeroes of p(x)

sum of the roots = α + β = –b/a

α + β = –6

product of roots = αβ = c/a

αβ = 8

So

α + β – αβ = – 6 – 8

α + β – αβ = – 14