if alpha and beta are the zeros of quadratic polynomial f(x) = x^2 -3x-2 find a polynomial whose zeros are 2alpha/beta and 2beta/ alpha
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Explanation:
alpha +beta= -b\a
alpha×beta= c/a
here a=1, b= -3 and c= -2
-b/a= (-(-3)/1 = 3/1 = 3
c/a= -2/1 = -2@
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