if alpha and beta are the zeros of quadratic polynomial f(x)= x square +px+q form a polynomial whose zeros are 1/alpha and 1/beta
Answers
Answer:
in the first case given that α and β are the zeroes of x²+px+q
sum of zeroes = α+β= -b/a {here a =1; b=p; c=q}
= -p/1
= -p-----(1)
product of zeroes = αβ=c/a
= q-----(2)
we need to find a polynomial whose zeros are 1/α and 1/β
sum of zeroes = 1/α+1/β
= (β+α)/αβ
= -p/q [ from equation (1) and (2)
product of zeroes = (1/α)(1/β)
= 1/αβ= 1/q [from equation 2 ]
now we need to find a polynoial whose sum is -p/q and product is 1/q
sum of zeroes = -p/q = -b/a
product of zeroes = 1/q = c/a
we can see that a =q; b = p; c= 1
Hence the required polynomial is qx²+px+1.
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