if alpha and beta are the zeros of quadratic polynomial
f( x )=aX^2+ bx + c.
then find the value of
1/alpha^3 +1/bita^3.
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step by step explanation☝
answer is 3abc-b^3 /c^3
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3abc - b^3/c^3
Step-by-step explanation:
1/alpha^3 + 1/beta^3 = alpha^3+ beta^3/alpha^3.beta^3
alpha+beta=-b/a
alpha. beta=c/a.
alpha^3+beta^3=(alpha+beta)^3 =alpha^3+beta^3+3alpha.beta(alpha+beta).
=3abc-b^3/a^3
from this on substitution
3abc-b^3/a^3/c^3/a^3=3abc-b^3/c^3
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