If alpha and beta are the zeros of quadratic polynomial f (x) = x^2-x-2.find a polynomial whose zeroes are (2alpha-1) and (2beta+1). Please answer me its very urgent.
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Thank you for asking this question. Here is your answer:
x²-3x+2=0
=x²-x-2x+2=0
=x(x-1)-2(x-1)=0
(x-1)(x-2)=0x=1
or ,
x=2 given zeroes of quadratic polynomial 1/2alpha+beta
1/2beta+alpha substitute=1/2(1)+2
1/2(2)+1=1/4
1/5formula is x²-(alpha+beta)x+alpha*beta =0therefore x²-
(1/4+1/5)x+1/4*1/5=0=ans is 20x^2 - 9x +1 =0
If there is any confusion please leave a comment below.
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