Question

if alpha and beta are the zeros of quadratic polynomial x cube -2xsq+3x-6 then find the value of alpha sq + beta sq -alpha beta​

Answer 1

Answer:

${x}^{3} - 2 {x}^{2} + 3x - 6 \\ = {x}^{2} (x - 2) + 3(x - 2) \\ = ( {x}^{2} + 3)(x - 2) \\ {x}^{2} =-3 = > x = \sqrt{3}i ,\:x=2 \\ \: \: \: \: \: \: \: { \alpha }^{2} \: \: \: \: \: \: \: \: \: \: ,\: \: \: \: \: \: \: \: \: \: \alpha \: \: \: \: \: \: \: \: \:, \: \: \: \: \: \: \: \: \beta \\ { \alpha }^{2} + { \beta }^{2} - \alpha \beta \\ = - 3 + 4 - \sqrt{3} i \times 2 \\ = 1 - 2 \sqrt{3} i \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$

Answer 2

Answer:

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