if alpha and beta are the zeros of the palynomial x^2+4x+3.find the quadratic polynomial whose zeros are 1+alpha/beta and 1+beta / alpha
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k(x²-2x )
Step-by-step explanation:
f(x)=x²+4x+3
⇒ 0=x²+x+3x+3
⇒ 0= x(x+1)+3(x+1)
⇒ 0=(x+1)(x+3)
∴x= -1,-3
or we can say that α=-1 and β=-3
∴ quadratic eq. having roots (1+α)÷β and (1+β)÷α
be ax² + bx + c
and roots can also be written as ( 1 +(-1))÷(-3)= 0
and( 1+(-3))÷(-1)= 2
∴-b/a=0+2=2
and c/a = 0 x 2 = 0
∴quadratic eq. is k(x²-2x )
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