Question

if alpha and beta are the zeros of the polymer such that alpha + beta is equal to 6 and alpha beta equal 4 then then write the polynomial​

Answer 1

Answer:

The answer will be (x^2 + 6x + 5) * k

Step-by-step explanation:

We Know That,

is alpha and beta are 2 roots of a polynomial f(x)... then f(x) will be

for a=1 , f(x) = x^2 - (alpha + beta)x + (alpha * beta)

and for a = k , f(x) = kx^2 - k*(alpha + beta)x + k*(alpha * beta)

i.e. k * (x^2 + 6x + 5)

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Answer 2

Answer:

x²-6x+4

Step-by-step explanation:

If p and q are the zeroes of a polynomial f(x). then, the given polynomial can be written as

f(x)=k(x-p)(x-q)=k{x²-(p+q)x+pq}, k is any real number.

Now, we have,

Sum of zeroes= 6

Product of zeroes= 4

So, the polynomial= k{x²-(sum of zeroes)x+ (product of zeroes)}

=k(x²-6x+4).

Putting K=1 we get

Required polynomial= x²-6x+4.(Ans).