If alpha and beta are the zeros of the polynomial 25^ x 2 – 15x + 2 then form the polynomial whose zeros are 2Alpha and 2Beta
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Answer:
- x² - 6x/5 + 8/25
Explanation:
Given polynomial,
⇒ 25x² - 15x + 2
On comapring with the general form of equation ax² + bx + c
- a = 25
- b = -15
- c = 2
Then,
- Sum of zeros = α + β = -b/a = 15/25 = 3/5 . . . . . . (i)
- Product of zeroes = αβ = c/a = 2/25. . . . (ii)
Now, given zeros are 2α & 2β
So, sum of the new zeros,
= 2α + 2β
= 2(α + β)
From (i) :-
= 2(3/5)
= 6/5
And also, product of new zeros,
= 2α.2β
= 4αβ
From (ii) :-
= 4(2/25)
= 8/25
Forming a quadratic equation,
⇒ x² - (sum of zeros)x + product of zeros
⇒ x² - (6/5)x + 8/25
⇒ x² - 6x/5 + 8/25
Required answer: x² - 6x/5 + 8/25
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