if alpha and beta are the zeros of the polynomial 25 x²- 16 then Alpha square plus beta square equals
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SOLUTION:-
α and β are the zeroes of the polynomial 25x² - 16 = 0.
25x² - 16 -> 25x² + 0x - 16 = 0
comparing with general form:- ax² + bx + c
we get :-
•°• a = 25, b = 0, c = -16
- now,
α + β = -b/a = -0/-16 = 0
•°• α + β = 0
And
α β = c/a = -16/25
•°• αβ = -16/25
- now,
α² + β² = (α + β)² - 2αβ .......formula
= 0² - 2 (-16/25)
= 0 + 32/25
α² + β² = 32/25
ANSWER
α² + β² equals to 32/25.
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Answer: \frac{1}{\alpha^{2}}+\frac. Step-by-step explanation: Given\:\alpha \:\beta \:are \\the\. Compare this polynomial with ax²+bx+c , we get. a = 25, b=25, c = 5. i)Sum\:of\:the\: zeroes ...
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