If alpha and beta are the zeros of the polynomial 25x2+25x+5, then find the value of 1/alpha2 +1/beta2
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sum of roots alpha +beta= -coefficient of x÷coefficient of x^2
alpha +beta=-25÷25
=-1
product of roots alpha×beta= constant term÷coefficient of x^2
alpha×beta=1÷5
I/alpha^2 + 1/beta^2
alpha^2 +beta^2 ÷ alpha^2 ×beta ^2
=((alpha +beta)^2 -2×alpha×beta)÷ (alphaxbeta)^2
=(1-2÷5)÷4÷25
(3÷5)÷(4÷25)
=15÷4
Answer the reciprocal of square of the roots of the numbers is 15÷4
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