if alpha and beta are the zeros of the polynomial 2x^2-5x+8 find the value of alpha^2 +beta^2
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Answer:
a2 +b2 = -7/4 = -1.75
Step-by-step explanation:
2X2 - 5X +8 is the polynomial
a, b are zeros of the polynomial
a+b = - (Co.eff of X)/(co.eff of X2)
ab = Constant term /(co.eff of X2)
a+b = -(-5)/2 =5/2 , ab = 8/2 =4
a2+b2 = (a+b)^2 - 2ab
a2+b2 = (5/2)^2 - 2(4)
= (25/4) - 8 = -7/4 = -1.75
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