Question

if alpha and beta are the zeros of the polynomial 2x^2+7x+5 then find 
\frac{1}{ \alpha } + \frac{1}{ \beta }α1​+β1​ 
plz help..

Wrong answer will be reported..​

Answer 1

Answer:

-7/5

Step-by-step explanation:

check the picture for correct answer

Answer 2

$\huge \boxed{ \blue{ \frac{ - 7}{5} }}$

Step-by-step explanation:

QUESTION :-

If $\alpha$ and $\beta$ are zeroes of the polynomial 2x² + 7x + 5, then find -

$\dfrac{1}{ \alpha } + \dfrac{1}{ \beta }$

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SOLUTION :-

2x² + 7x + 5

In the standard form of quadratic equation (ax² + bx + c), here -

• a = 2
• b = 7
• c = 5

We know that,

sum of zeroes $\alpha + \beta = \frac{-b}{a} = \frac{-7}{2}$

product pf zeroes $\alpha \beta = \frac{c}{a} = \frac{5}{2}$

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Now,

$\frac{1}{ \alpha } + \frac{1}{ \beta } \\ \\ = > \frac{ \alpha + \beta }{ \alpha \beta } ... \tiny{taking \: LCM \: as \: \alpha \beta }$

Put the value of $\alpha + \beta \: \& \alpha \beta$

$\\ = > \frac{ \: \frac{ - 7}{2} }{ \frac{5}{ \: 2} } \\ \\ \\ = > \frac{ - 7}{2} \div \frac{5}{2} \\ \\ = > \frac{ - 7}{ \cancel{2 }} \times \frac{ \cancel{2}}{5} \\ \\ = > \frac{ - 7}{5}$

So,

The value of

$\large \frac{1}{ \alpha } + \frac{1}{ \beta } = \frac{ - 7}{5}$

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Hope it helps.

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