if alpha and beta are the zeros of the polynomial 3 x square - 7 x + K andand 2 Beta -3 Alpha is equals to 3 find the value of k
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Step-by-step explanation:
3x^2-7x+k=0
sum of zeros=(-b/a)
alpha+beta=7/3
3alpha+3beta=7.......(1)
product of zeros =c/a
alpha*beta=k/3 ........(2)
now,
Add. . 3alpha+3beta=7
-3alpha+2beta=3
..,...............................
5beta=10
beta =2
from eq(1),
3alpha+3(2)=7
3alpha=1
alpha=1/3
from eq(2),
(1/3)*2=k/3
k=2
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