Question

if alpha and beta are the zeros of the polynomial 3 X square + 2 X + 3 then find one by Alpha square + 1 by beta square.​

Answer 1

Answer:

(1+(α+β)+αβ1−(α+β)+αβ)⎣⎢⎢⎡1−32+311+32+31⎦⎥⎥⎤[22×3]=3=(1+α+β+αβ)(1−α)(1+β)+(1−β)(1+α)=321+β−α−αβ+1+α−β−αβ=23(2−2αβ)=3(1−αβ)=3(1−31)=2

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Answer:

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