If alpha and beta are the zeros of the polynomial 3s^2 - 6x + 4 , find the value of alpha / beta +2(1/alpha + 1/beta )+3alpha beta
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Given -
α and β are zeros of
3x²-6x+4 =0
It means
α+β = 6/3 = 2
αβ = 4/3
α and β are zeros of
3x²-6x+4 =0
It means
α+β = 6/3 = 2
αβ = 4/3
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