if alpha and beta are the zeros of the polynomial 3x^2 +11x -4 then the value of alpha^2+beta^2 is
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Answer:
145/9
Step-by-step explanation:
Given equation,
3x² + 11x -4
Roots of equation are α and β
equation can be written as
3x² + 12x - 1x -4
3x(x + 4) - 1(x + 4)
(x + 4) (3x - 1)
x = -4 and 1/3
α and β are -4 and 1/3
α² = (-4)² = 16
β² = (1/3)² = 1/9
now
α² + β² = 16 + 1/9
= 145/9
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