Question

If alpha and beta are the zeros of the polynomial 3x^2 - 4x - 7 then find the sum of their reciprocals.

Answer 1

$p(x) = 3x^{2} - 4x - 7 = 0 \\ \alpha + \beta = - b \div a \\ \alpha + \beta = 4 \div 3 \\ \alpha \beta = c \div a \\ \alpha \beta = - 7 \div 3 \\ recprocal \: of \: of \: sum = \alpha + \beta \div \alpha \beta = 4 \div 3 \div - 7 \div 3 \\ \alpha + \beta \div \alpha \beta = - 4 \div 7$

answer is -4/7

Answer 2

Answer:

hiiii ii................................