Question

If alpha and beta are the zeros of the polynomial 5x^2 + 4x- 9 than evaluate the following : (1) alpha - beta , (2) alpha^2 + beta^2 , (3) alpha^2 - beta^2 , (4) alpha^3 + beta^3 , (5) alpha^3 - beta^3 , (6) alpha^4 - beta^4 .

Answer 1

this is the answer
$5 {x}^{2} + 4x - 9 = 0 \\ 5x {}^{2} - 5x + 9x - 9 = 0 \\ 5x(x - 1) + 9((x - 1) = 0 \\ (5x + 9) (x - 1) = 0 \\ 5x + 9 = 0...x = \frac{ - 9}{5} \\ x - 1 = 0...x = 1 \\ \alpha = 1 ...\beta = \frac{ - 9}{5} \\ \alpha - \beta = 1 - ( \frac{ - 9}{5} ) \\ = 1 + \frac{9}{5} \\ = \frac{14} {5}$

Answer 2

5x2 +4x-9

factorise the eq.

(5x +9)(x-1)=0

Then X = -9/5and beta=1

1.-4/5

2.106/25

3.54/25

Last three points you can solve.......

By the value of alphA and bEta

............this answer..............

Help you...........

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