Question

if alpha and beta are the zeros of the polynomial 6x2+x-2 find alpha /beta+beta/alpha. Please answer using dum of zeros and product of zeros​

Answer 1

Answer:

alpha=2

beta=-2/3

Step-by-step explanation:

$6x {}^{2} + x - 2 \: \: \: spliting \: the \: midle \: term\\ 6x { }^{2} - 3 x + 4x - 2 \\ 3x( - 2x ) + 2( - 2x) \\ \alpha = - 2x = x = 2 \\ \beta = 3x + 2 = x = - 2 \div 3$