Question

if alpha and beta are the zeros of the polynomial 6y^ 2 - 7y + 2 find the quadratic polynomial whose zeros are 1 by Alpha and one by beta​

Answer 1

Answer:

alpha + beta = - b / a

alpha + beta = 7 / 6

aplpha * beta = c/a

alpha * beta = 1/ 3

alpha + beta = - b / a

7 / 6 = - b / a

1/ 3= c/a

c / a = (1/ 3)*2/ 2

a = 6

b = -7

c = 2

therefore 6x square - 7x + 2