If alpha and beta are the zeros of the polynomial f(x):- 3*x^2-4*x+1 and find a quadratic polynomial zeros are alpha square/beta and beta square/alpha
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Answered by
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hi friend ,
given f(x)=3x²-4x+1
→3x²-3x-x+1
→3x(x-1)-1(x-1)
→(3x-1)(x-1)
so œ,ß are 1/3,1
œ²/ß=1/9---(1)
ß²/œ=3---(2)
given.(1) and (2) are zeros of a polynomial
sum of zeros =1/9+3=28/9
product of zeros =1/3
so polynomial will be
→x²-(28/9)x+1/3
I hope this will help u :)
given f(x)=3x²-4x+1
→3x²-3x-x+1
→3x(x-1)-1(x-1)
→(3x-1)(x-1)
so œ,ß are 1/3,1
œ²/ß=1/9---(1)
ß²/œ=3---(2)
given.(1) and (2) are zeros of a polynomial
sum of zeros =1/9+3=28/9
product of zeros =1/3
so polynomial will be
→x²-(28/9)x+1/3
I hope this will help u :)
Answered by
2
Hello!
3x²-4x+1
3x²-3x-x+1
3x(x-1)-1(x-1)
(3x-1)(x-1)
x= 1/3 , 1
If α²/β,β²/α are the roots
α²/β=1/9
β²/α=3
x²-(α+β)x+αβ
x²-(3+1/9)x+1/3
x²-28/9x+1/3
9x²-28x+3 is the required polynomial .
hope helped
3x²-4x+1
3x²-3x-x+1
3x(x-1)-1(x-1)
(3x-1)(x-1)
x= 1/3 , 1
If α²/β,β²/α are the roots
α²/β=1/9
β²/α=3
x²-(α+β)x+αβ
x²-(3+1/9)x+1/3
x²-28/9x+1/3
9x²-28x+3 is the required polynomial .
hope helped
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