If ALPHA and BETA are the zeros of the polynomial f(x) = 3x2 – 2x – 21, then find the value of 1/ALpha - 1/BETA
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Answer:
Given Polynomial:- 3x²-2x-7
Now..
Sum of zeroes=-b/a=-(-2)/3=2/3
Product of Zeroes=c/a=-7/3
ACCORDING TO THE QUESTION....
a/b+b/a
=)a²+b²/ab
= ( a + b)² - 2ab /ab
= ( 2/3)² - 2× -7/3 ÷ 7/3
= (4/9 + 14/3 ) ÷ 7/3
= 4 + 42/9 ÷ 7/3
= 46/9 ÷ 7/3
= 46/9 × 3/7
= 46/3 × 1/7
= 46/21
Hope it work
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