Math, asked by samanvo4, 2 months ago

If alpha and beta are the zeros of the polynomial f (x)=x^-p(x+1)-c then find the value of (alpha+1) (beta+1)​

Answers

Answered by pranjaligupta2106
1

We have,

f(x)=x

2

−p(x+1)−c=0

f(x)=x

2

−px−(p+c)=0

So,

α+β=p

αβ=−(p+c)

Since,

(α+1)(β+1)=0

αβ+α+β+1=0

−p−c+p+1=0

−c+1=0

c=1

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