If alpha and beta are the zeros of the polynomial f (x)=x^-p(x+1)-c then find the value of (alpha+1) (beta+1)
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We have,
f(x)=x
2
−p(x+1)−c=0
f(x)=x
2
−px−(p+c)=0
So,
α+β=p
αβ=−(p+c)
Since,
(α+1)(β+1)=0
αβ+α+β+1=0
−p−c+p+1=0
−c+1=0
c=1
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