Math, asked by Answers1334, 1 year ago

if alpha and beta are the zeros of the polynomial f(X)=x2-3x+6find the value of 1/alpha+1/beta+alpha2+beta2-2alpha beta

(Pls answer)

Answers

Answered by BEJOICE
0

f(x) =  {x}^{2}  - 3x + 6 \\  \alpha  +  \beta  = 3 \:  \:  \:  \:  \:  \:  \:  \:  \alpha  \beta  = 6 \\  \frac{1}{ \alpha }  +  \frac{1}{ \beta }  +  { \alpha }^{2}  +  { \beta }^{2}  - 2 \alpha  \beta  \\  =  \frac{ \alpha  +  \beta }{ \alpha  \beta }  +  {( \alpha  +  \beta )}^{2}  - 4 \alpha  \beta  \\  =  \frac{3}{6}  +  {3}^{2}  - 4 \times 6 =  \frac{ - 29}{2}
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