if alpha and beta are the zeros of the polynomial f(x)= x²-p(x+1)-c such that (alpha+1) (beta+1)=0 them the value of c is
a) 1
b) 0
c) -1
d) -2
URGENT!!!
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0
Answer:
c=1
Step-by-step explanation:
Expand the equation
→x²-p(x+1)-c
→x²-px-(p+c)
according to quadratic equation
sum of root are æ+ß=-b/a
product of roots æß=c/a
→(alpha+1) (beta+1)=0
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