If alpha and beta are the zeros of the polynomial
fx=(4x2+ 3x+ 7 ) then find the value of 1/alpha and 1/beta
Answers
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3
Answer:
Given: α,β are zeroes of the polynomial 4x
2
+3x+7
To find the value of
α
1
+
β
1
We know that equation ax
2
+bx+c=0
Then sum of roots =
a
−b
and product of roots=
a
c
From the given quadratic equation,
α+β=−
4
3
and αβ=
4
7
Therefore,
α
1
+
β
1
=
αβ
α+β
=
4
7
−
4
3
=−
7
3
⇒
α
1
+
β
1
=−
7
3