If alpha and beta are the zeros of the polynomial p(x)= 4xsquare - 2x - 3 find the value of 1/alfa + 1/beta
Answers
Answer:
- 2 / 3
Step-by-step explanation:
Given----> α and β are the zeroes of the polynomial P ( x ) = 4x² - 2x - 3 .
To find---> find the value of ( 1 / α + 1 / β )
Solution---> ATQ,
P( x ) = 4x² - 2x - 3
Zeroes of above polynomial are α and β .
We know that ,
Sum of zeroes = - Coefficient of x/Coefficient of x²
=> α + β = - ( - 2 ) / 4
=> α + β = 1 / 2
Product of zeroes
= Constant term/Coefficientof x²
=> α β = -3 / 4
Now,
1 / α + 1 / β = ( α + β ) / αβ
= ( 1 / 2 ) / ( -3 / 4 )
= - 4 / 6
= - 2 / 3
Answer:
Step-by-step explanation:
Given----> α and β are the zeroes of the polynomial P ( x ) = 4x² - 2x - 3 .
To find---> find the value of ( 1 / α + 1 / β )
Solution---> ATQ,
P( x ) = 4x² - 2x - 3
Zeroes of above polynomial are α and β .
We know that ,
Sum of zeroes = - Coefficient of x/Coefficient of x²
=> α + β = - ( - 2 ) / 4
=> α + β = 1 / 2
Product of zeroes
= Constant term/Coefficientof x²
=> α β = -3 / 4
Now,
1 / α + 1 / β = ( α + β ) / αβ
= ( 1 / 2 ) / ( -3 / 4 )
= - 4 / 6
= - 2 / 3