if alpha and beta are the zeros of the polynomial P(X) = X square + X - 6 then find the value of 1 by Alpha square + 1 by beta square
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Hey Mate ✌
↪ Here's your answer friend,
Given : P(x) ==> x² + x - 6 = 0
==> x² + 3x -2x - 6 = 0
==> x(x + 3) -2(x + 3) = 0
==> (X + 3)(X - 2) = 0
==>x = -3 or x = 2
Therefore,
α² + β² = (-3)² + (2)²
==> 9 + 4 = 13
is the required answer ^_^
Hope it helps you
↪ Here's your answer friend,
Given : P(x) ==> x² + x - 6 = 0
==> x² + 3x -2x - 6 = 0
==> x(x + 3) -2(x + 3) = 0
==> (X + 3)(X - 2) = 0
==>x = -3 or x = 2
Therefore,
α² + β² = (-3)² + (2)²
==> 9 + 4 = 13
is the required answer ^_^
Hope it helps you
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