if alpha and beta are the zeros of the polynomial such that alpha + beta is equal to 6 and alphabet is equal to 4 then write the polynomial
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Answered by
9
alpha + beta = 6
alpha × beta = 4
Therefore,
required polynomial = X²-(alpha+ beta ) X + (alpha × beta) .
= X²-(6)X+ 4
= X²-6X+4
alpha × beta = 4
Therefore,
required polynomial = X²-(alpha+ beta ) X + (alpha × beta) .
= X²-(6)X+ 4
= X²-6X+4
Answered by
2
Alpha+beta=6
Beta=6-4=2
So, the polynomial is:
xsq-Sx+P
=xsq-6x+(4*2)
=xsq-6x+8
Beta=6-4=2
So, the polynomial is:
xsq-Sx+P
=xsq-6x+(4*2)
=xsq-6x+8
Oliveka:
Xsq-sx+p is a general formula
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