Question

If alpha and beta are the zeros of the polynomial such that alpha + beta = 10 and alpha.beta=6. write the polynomial

Answer 1

${x}^{2} - 10x + 6 = 0$
We know that the quadratic polynomial is of the form
${x}^{2} - sx + p$
Where s is the sum of roots and P is the product of the roots.
Substituting the values, we get the polynomial as written above.

Answer 2

Answer:

$\huge\boxed{\underline{\underline{\pink{hello mate}}}}$

$\mathcal{\green{answer = {x}^{2} + 10x + 6 }}$

Step-by-step explanation:

Given that,the sum of Zeroes =10

the product of zeros =6

To form a quadratic polynomial

we have to use the formula, '

${x}^{2} - ( \alpha + \beta )x + \alpha \beta$

So we get ,

$= {x}^{2} + 10x + 6$

Hence, the required polynomial is x²+10x+6.

$</strong><strong><</strong><strong>marquee</strong><strong>></strong><strong>{ thank you</strong><strong>}$