Question

if alpha and beta are the zeros of the polynomial t^2 - 4t + 3 find Alpha/Beta + beta/alpha + 2

Answer 1

Answer: 10/3

Step-by-step explanation:

Given polynomial = $t^{2} - 4t +3$

Solving this polynomial by splitting the middle term method:

$t^2-3t-t+3\\t(t-3)-1(t-3)\\\\(t-1)(t-3)$

Here , t = 1 and t = 3

So its zeroes are 1 and 3 respectively. Also,

α = 1 and β = 3

According to the question, we've to find,

α/β + β/α + 2

1/3 + 3/1 +2

4/3 + 2

10/3