If alpha and beta are the zeros of the polynomial t^2 - 4t + 3 find (alpha+1)(beta+1)
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HELLO DEAR,
given equation is t² - 4t + 3 = 0
therefore, t² - 3t - t + 3 = 0
t(t - 3) - 1(t - 3) = 0
(t - 1)(t - 3) = 0
hence, alpha = t = 1 and beta = t = 3
thus, (alpha + 1) = 1 + 1 = 1
(beta + 1) = 3 + 1 = 4
I HOPE IT'S HELP YOU DEAR,
THANKS
given equation is t² - 4t + 3 = 0
therefore, t² - 3t - t + 3 = 0
t(t - 3) - 1(t - 3) = 0
(t - 1)(t - 3) = 0
hence, alpha = t = 1 and beta = t = 3
thus, (alpha + 1) = 1 + 1 = 1
(beta + 1) = 3 + 1 = 4
I HOPE IT'S HELP YOU DEAR,
THANKS
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