Question

If alpha and beta are the zeros of the polynomial x^2+4x+3. Find the polynomial where zeroes are 1+beta by alpha and 1+alpha by beta.
Please send me the answer
Please.....

Answer 1

Answer:

x^2-2x=0x2−2x=0

Step-by-step explanation:

First of all, factorize the given polynomial:

\begin{lgathered}x^2+4x+3=0\\(x+3)(x+1)=0\\x=-3\:\:or\:\:x=-1\end{lgathered}x2+4x+3=0(x+3)(x+1)=0x=−3orx=−1

Let the -3 be the α, and the -1 be the β.

It is required to find the polynomials which have the roots of:

x=\frac{1+\beta}{\alpha}x=α1+β and x=\frac{1+\alpha}{\beta}x=β1+α .

Substitute by α=-3, and β=-1:

Therefore, the roots are: x = 0 and x = 2

Therefore, the polynomial must be: x(x-2)=0

Polynomial: x^2-2x=0x2−2x=0

hope this will help you ❤

.

.

mark me as brainliest ❤❤pls pls