if alpha and beta are the zeros of the polynomial x^2-x-12=0 then form a quadratic equation whose zeros are 2alpha,2beta
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x^2-x-12=0 => x^2-4x+3x-12=0 => x(x-4)+3(x-4) =0
=> (x-4)(x+3) =0 => x=4 or x=-3.
Let alpha=4 and beta=-3
Then, 2 alpha=(2*4)=8 and 2 beta=(-3*2)=-6.
Hence, the required equation
= x^2-(2 alpha+2 beta)x+2 alpha 2 beta
x^2- {8+(-6)}x + {8*(-6)} = x^2-2x-48.
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