if alpha and beta are the zeros of the polynomial x
-p (x + 1) -c then (alpha +1) (beta + 1)is equal to
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Given : α and β are zeroes of the polynomial
x² - p(x + 1) - c
To Find : (α + 1)(β + 1)
Solution:
polynomial x² - p(x + 1) - c
= x² - px - p - c
= x² - px - (p + c)
Sum of zeroes = α + β = -(-p)/1 = p
Product of zeroes = αβ = -(p + c)/1 = - (p + c)
(α + 1)(β + 1)
= αβ + α + β + 1
= - (p + c) + p + 1
= -c + 1
= 1 - c
(α + 1)(β + 1) = 1 - c
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