Math, asked by saurabhmittal1112, 11 months ago

If alpha and beta are the zeros of the polynomial x square minus 4x +2 then find the value of (alpha+1)-2 +(beta+ 1)-2

Answers

Answered by Anonymous
20

\huge\tt{\red{\underline{Given:}}}

★A polynomial  x^{2}-4x+2

\alpha & \beta are the zeroes of the polynomial.

\huge\tt{\red{\underline{To\:\:Find:}}}

(\alpha+1) -2+(\beta+1) -2

\huge\tt{\red{\underline{Concept\:\:Used:}}}

★We will find it's zeroes by the method of factorisation.

\huge\tt{\red{\underline{Answer:}}}

We have,

\implies x^{2}-4x+2=0

\implies x^{2}-2x-2x+2=0

\implies x(x-2) -2(x-1) =0

\implies (x-2) (x-1) =0

.°.\underline{\boxed{ x = 2,1}}

______________________________________

Let

  • \alpha =2
  • \beta =  1

.°. (\alpha+1) -2+(\beta+1) -2

= (2+1) -2+(1+1) -2

=3 \times -2 + 2 \times -2

=-6-4

=-10

Therefore the required answer is -10.

\huge\orange{\boxed{(\alpha+1) -2+(\beta+1) -2= -10}}

Answered by Anonymous
1

Step-by-step explanation:

 \alpha  \: and \:  \beta  \: are \: zeroes \: of \: the \: polynomial

we \: have

x ^{2}  - 4x + 2

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