if alpha and beta are the zeros of the polynomial X square + 4 x + 3 find the quadratic polynomial whose zeros are 1 + Alpha upon beta and 1 + beta upon Alpha
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Answer:
x²-(sum)+(P)
x²-(2x)+0
Step-by-step explanation:
we have, x²+4x+3. a+b=-4 & ab=3
1.sum of given zeroes
1+a/b + 1+b/a = a+a²+b+b²/ab
= -4+(-4)²-2×3/3
=-4+16-6/3
=-10+16/3
=6/3
=2
alpha+beta=-b/a=2
2.and product of zeroes
(1+a/b)(1+b/a)
=1+b+a+ab/ab
=1+(-4)+3/3
=1-4+3/3
=0/3
alpha × beta =c/a=0
HENCE,X²-SUM+PRODUCT= x²-(2)+0
I HOPE THIS WILL HELP YOU.
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