if alpha and beta are the zeros of the polynomial x square - 5 x + K such that Alpha minus beta equals to 1 find k
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Heya!!!
Alfa - Beta = 1 ( Given )
For a general quadratic equation i,e
ax² + bx + c = 0
Alfa + Beta = -b/a And Alfa × Beta =c/a
______________________________
Alfa + Beta = 5 And Alfa × Beta = k
=>
Alfa - Beta = √ {( Alfa + Beta )² - 4Alfa ×
Beta}
=>
Alfa - Beta = 1 ( Given )
= >
1 = √{ ( 5 )² - 4k }
SQUARING BOTH SIDE'S!
5 + 4k = 1 OR 5 + 4k = -1
4k = -4 OR 4k = -6
k = -1 OR k = -3/2
Alfa - Beta = 1 ( Given )
For a general quadratic equation i,e
ax² + bx + c = 0
Alfa + Beta = -b/a And Alfa × Beta =c/a
______________________________
Alfa + Beta = 5 And Alfa × Beta = k
=>
Alfa - Beta = √ {( Alfa + Beta )² - 4Alfa ×
Beta}
=>
Alfa - Beta = 1 ( Given )
= >
1 = √{ ( 5 )² - 4k }
SQUARING BOTH SIDE'S!
5 + 4k = 1 OR 5 + 4k = -1
4k = -4 OR 4k = -6
k = -1 OR k = -3/2
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