if alpha and beta are the zeros of the polynomial X square + bx + c find the value of Alpha minus beta Alpha square plus beta square
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\begin{lgathered}\alpha + \beta = - b \div a \\ \\ \alpha \beta = c \div a \\ \\ \alpha - \beta = \sqrt{} (\alpha + \ \beta ) {}^{2} \: - 4 \alpha \beta \\ \\ \alpha - \beta = \sqrt{(b {}^{2} } \div a {}^{2} ) - 4c \div a\end{lgathered}α+β=−b÷aαβ=c÷aα−β=(α+ β)2−4αβα−β=(b2÷a2)−4c÷a
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\begin{lgathered}\alpha + \beta = - b \div a \\ \\ \alpha \beta = c \div a \\ \\ \alpha - \beta = \sqrt{} (\alpha + \ \beta ) {}^{2} \: - 4 \alpha \beta \\ \\ \alpha - \beta = \sqrt{(b {}^{2} } \div a {}^{2} ) - 4c \div a\end{lgathered}α+β=−b÷aαβ=c÷aα−β=(α+ β)2−4αβα−β=(b2÷a2)−4c÷a
HOPE IT HELPS. ✌✌
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