if alpha and beta are the zeros of the polynomial x square - 8 x + A and and Alpha square minus beta square equal to 40 find the value of a
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here is your answer by Sujeet,
Given that zeroes of polynomial,
alpha and beta,
x²-8x+a
then,
a+b=8
a=8-b
Now putting the value in a polynomial,
a²-b²=40
(a+b)(a-b)=40
8(a-b)=40
a-b=40/8
a-b=5
then,
Now putting the value of a in equation,
a-b=5
8-b-b=5
8-2b=5
-2b=5-8
-2b=-3
b=3/2
now putting the value of a,
a+b=8
a+3/2=8
a=8/1-3/2
a=13/2
then,
Product of zeroes=c/a
a×b=a/1
13/2×3/2
39/4=a/a
a=39/4
Given that zeroes of polynomial,
alpha and beta,
x²-8x+a
then,
a+b=8
a=8-b
Now putting the value in a polynomial,
a²-b²=40
(a+b)(a-b)=40
8(a-b)=40
a-b=40/8
a-b=5
then,
Now putting the value of a in equation,
a-b=5
8-b-b=5
8-2b=5
-2b=5-8
-2b=-3
b=3/2
now putting the value of a,
a+b=8
a+3/2=8
a=8/1-3/2
a=13/2
then,
Product of zeroes=c/a
a×b=a/1
13/2×3/2
39/4=a/a
a=39/4
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