if alpha and beta are the zeros of the polynomials x²-5x+6 find a polynomial whose zeros are (i)alpha/beta and beta/alpha (ii)alpha+1/alpha-1 and beta+1/beta-1
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x2-5x+6
x2-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-2)(x-3)=0
x=2,x=3
therefore zeroes of polynomial of x2-5x+6 are 2,3
alpha =2and beta3
sum of zeroes alpha +beta =-b/a
2+3=-(-5)/1
5=5
product of zeroes are aplha×beta =c/a
2×3=6
6=6
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