If Alpha and beta are the zeros of the poynomial
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Alpha + Beta = -2/3
Alpha × Beta = 1/3
[(1-a) *(1+b)+ (1-b) * (1+a)]/ 1 - ab
= 2(1- ab)/ 1- ab
= 2
Where a = alpha
b = beta
Alpha × Beta = 1/3
[(1-a) *(1+b)+ (1-b) * (1+a)]/ 1 - ab
= 2(1- ab)/ 1- ab
= 2
Where a = alpha
b = beta
dhruv77tayal:
wrong
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