Question

if alpha and beta are the zeros of the quadratic polynomial 2 X square + 3 x minus 5 find the value of one by Alpha Plus One by beta

Answer 1

Step-by-step explanation:

alpha + beta =-3/2

alpha×beta=-5/2

1/alpha+1/beta=alpha+beta/alpha×beta

by putting values

-3/2÷-5/2=-3×2/-5×2

=3/5 Answer...

Answer 2

The value of  $\dfrac{1}{\alpha}+ \dfrac{1}{\beta} \text { is } \dfrac{3}{5}$

Step-by-step explanation:

Given: α and β are the zeroes of quadratic polynomial $2x^2+3x-5$

To find:  $\dfrac{1}{\alpha}+ \dfrac{1}{\beta}$

As we know $ax^2+bx+c$ is a general form of quadratic polynomial

Therefore by comparing

a= 2, b= 3, c= -5

Now as we know

$\alpha+\beta= \dfrac{-b}{a} = \dfrac{-3}{2}$

$\alpha\beta = \dfrac{c}{a} = \dfrac{-5}{2}$

Now we have to find

$\dfrac{1}{\alpha}+ \dfrac{1}{\beta}=\dfrac{\alpha+\beta}{\alpha\beta} =\dfrac{\dfrac{-3}{2} }{\dfrac{-5}{2} } =\dfrac{3}{5}$

Hence, the value of $\dfrac{1}{\alpha}+ \dfrac{1}{\beta} \text { is } \dfrac{3}{5}$

#Learn more

If alpha and beta are the zeroes of the polynomial 2x^2-7x+3. find the sum of the reciprocal of its zeroes

brainly.in/question/2796393