if alpha and beta are the zeros of the quadratic polynomial 2 X square + 3 x minus 5 find the value of one upon alpha plus one upon beta
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Step-by-step explanation:
(2x^2)+3x-5 = 0
(2x^2) + 5x - 2x -5 =0
x*(2x+5)-1*(2x+5) =0
(x-1) (2x+5) =0
beta = (2x+5) =0. i.e x= (-5/2)
alpha = (x-1)= 0 i.e x =1
(1/alpha) = (1÷1) = 1
(1/beta) = 1÷( -5/2) = (-2/5)
therefore (1) -( 2/5)
= (3/5)
is the required answer
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5
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