Question

if alpha and beta are the zeros of the quadratic polynomial f of X equal to 6 X square + X minus 2 then find the value of Alpha minus beta​

Answer 1

Answer:

1, 4

Step-by-step explanation:

$6 {x}^{2} + x - 2 \\ = 6 {x }^{2} + 4x - 3x - 2 \\ = 2x(3x + 2) - 1(3x + 2) \\ =(3x + 2)(2x - 1) \\ 3x + 2 = 0 \: or \: 2x - 1 = 0 \\ x = - 2 \div 3or \: x = 1 \div 2$