If alpha and beta are the zeros of the quadratic polynomial AXsquare+bx +c . Find the value of alpha square +beta square
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Answer:
Quadratic equation=ax²+bx+c
Then,alpha+beta=-b/a
,alpha×beta=c/a
Now,alpha+beta=-b/a
(alpha+beta)²=(-b/a)².
{Both side squaring}
alpha²+beta²+2alpha.beta=b²/a²
alpha²+beta²+2×c/a=b²/a²
alpha²+beta²+2c/a=b²/a²
alpha²+beta ²=b²/a²-2c/a
alpha ²+beta²=b²-2ac/a²
Step-by-step explanation:
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